使用flask-restful实现数据校验与序列化3

This commit is contained in:
zhengxinonly
2021-06-27 19:27:08 +08:00
parent e9bd8a17a0
commit e3dd5458ad
23 changed files with 517 additions and 1202 deletions
+66 -1
View File
@@ -3,8 +3,11 @@ from collections import OrderedDict
from flask import current_app
from flask_login import current_user
from flask_restful import marshal
from applications.models import PowerSchema
from applications.common.serialization import power_fields
from applications.extensions import db
from applications.models import PowerSchema, Power, Role, User
def get_render_config():
@@ -115,3 +118,65 @@ def make_menu_tree():
return menu_dict.get(0)
# 选择父节点
def select_power_dict():
power = Power.query.all()
res = marshal(power, power_fields)
res.append({"powerId": 0, "powerName": "顶级权限", "parentId": -1})
return res
def get_power_dict():
power = Power.query.all()
res = marshal(power, power_fields)
return res
# 删除权限(目前没有判断父节点自动删除子节点)
def remove_power(power_id):
power = Power.query.filter_by(id=power_id).first()
role_id_list = []
roles = power.role
for role in roles:
role_id_list.append(role.id)
roles = Role.query.filter(Role.id.in_(role_id_list)).all()
for p in roles:
power.role.remove(p)
r = Power.query.filter_by(id=power_id).delete()
db.session.commit()
return r
# 批量删除权限
def batch_remove_power(ids):
for _id in ids:
remove_power(_id)
def remove_role(_id):
""" 删除角色 """
role = Role.query.filter_by(id=_id).first()
# 删除该角色的权限
power_id_list = []
for p in role.power:
power_id_list.append(p.id)
powers = Power.query.filter(Power.id.in_(power_id_list)).all()
for p in powers:
role.power.remove(p)
user_id_list = []
for u in role.user:
user_id_list.append(u.id)
users = User.query.filter(User.id.in_(user_id_list)).all()
for u in users:
role.user.remove(u)
r = Role.query.filter_by(id=_id).delete()
db.session.commit()
return r
def batch_remove_role(ids):
""" 批量删除 """
for _id in ids:
remove_role(_id)