优化curd函数在view的引入方式,优化权限与日志的装饰器
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from io import BytesIO
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from flask import session, make_response
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from flask_login import current_user
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from applications.models.admin_power import PowerSchema
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from applications.service.CaptchaTool import gen_captcha
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# 授权路由存入session
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def add_auth_session():
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role = current_user.role
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user_power = []
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for i in role:
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if i.enable == 0:
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continue
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for p in i.power:
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if p.enable == 0:
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continue
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user_power.append(p.code)
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session['permissions'] = user_power
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# 生成菜单树
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def make_menu_tree():
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# power0 = Power.query.filter(
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# Power.type == 0,
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# ).all()
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# power1 = Power.query.filter(
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# Power.type == 1
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# ).all()
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role = current_user.role
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power0 = []
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power1 = []
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for i in role:
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if i.enable == 0:
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continue
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for p in i.power:
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if p.enable == 0:
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continue
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if int(p.type) == 0:
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power0.append(p)
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else:
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power1.append(p)
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power_schema = PowerSchema(many=True) # 用已继承ma.ModelSchema类的自定制类生成序列化类
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power0_dict = power_schema.dump(power0) # 生成可序列化对象
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power1_dict = power_schema.dump(power1) # 生成可序列化对象
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power0_dict = sorted(power0_dict, key=lambda i: i['sort'])
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power1_dict = sorted(power1_dict, key=lambda i: i['sort'])
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# print(power0)
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# print(power1)
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menu = []
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for p0 in power0_dict:
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for p1 in power1_dict:
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if p0.get('id') == p1.get('parent_id'):
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if p0.get("children") is None:
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p0['children'] = []
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p0['children'].append(p1)
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menu.append(p0)
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return menu
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# 生成验证码
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def get_captcha():
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code, image = gen_captcha()
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out = BytesIO()
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session["code"] = code
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image.save(out, 'png')
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out.seek(0)
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resp = make_response(out.read())
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resp.content_type = 'image/png'
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return resp, code
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